
After burning 1.5g of some gas, 4.4g of CO2 and 2.7g of H2O ... - Socratic
Aug 26, 2016 · After burning 1.5g of some gas, 4.4g of CO2 and 2.7g of H2O were produced. What is this gas if at STP 1L of this gas weighs 1.34g? ChemistryGasesIdeal Gas Law
Question #5231b - Socratic
Mar 27, 2018 · Assuming you're referring to the decomposition reaction 2NaHCO3 → Na2CO3 + H2O+ CO2, 3.0mol NaHCO3 × 1mol CO2 2mol NaHCO3 = 1.5mol CO2
Question #73e9b + Example - Socratic
They are the same in that they have a coefficient multiplied by 10 raised to a power. However, in exponential notation there is no set way to write the coefficient, whereas in scientific notation the …
Question #ab45a - Socratic
Feb 12, 2016 · Baking soda is NaHCO3 and Vinegar is CH3COOH their reaction in aqueous solution is NaHCO3 +CH3COOH -->CO2 +H2O + CH3COONa . Solution will contain sodium acetate and …
Site Map - Percent Concentration Questions and Videos | Socratic
Given the following equation: C6H8O7 + 3NaOH --> Na3C6H5O7 + H2O. What is the percentage by mass of citric acid in the orange juice? How many grams of HCI are there in 100.0 mL of …
Question #00338 - Socratic
We're asked to find the molarity of the HCl in the gastric juice with some given titration data. First, let's write the balanced chemical equation for this neutralization reaction: NaOH(aq) + HCl(aq) → …
Question #961df - Socratic
Boyle's law holds that for a given quantiy of gas, P prop 1/V, or PxxV=k; so if the pressure is doubled the the volume is halved, and vice versa. Given that P and V are inversely proportional, if the pressure …
Question #862f2 - Socratic
Feb 4, 2016 · 2HCl +CrO3 → CrO2Cl2 + H2O If you add these equations together (and balance them out), you'll get the chemical equation that describes the overall reaction. I think that some chlorine …
What were theropods? - Socratic
Theropod dinosaurs are a diverse group of bipedal Saurischian dinosaurs. They were the top predators in the Jurassic and Cretaceous periods. For over 100 million years they were the largest carnivores …
Question #3b716 - Socratic
I assume that the poster meant: y=e^x tan sqrt {5x} By rewriting the square-root as the 1/2-power, y=e^xtan (5x)^ {1/2} Let us now find the derivative. By Product Rule, y'= (e^x)'cdot tan (5x)^ …